Python If-Else hackerrank solution

 

Task
Given an integer, , perform the following conditional actions:

·        If n is odd, print Weird

·        If  n is even and in the inclusive range of  to , print Not Weird

·        If n   is even and in the inclusive range of  to , print Weird

·        If  n is even and greater than , print Not Weird

Input Format

A single line containing a positive integer, .

Constraints

·        1<=n<=100

Output Format

Print Weird if the number is weird. Otherwise, print Not Weird.

Sample Input 0

3

Sample Output 0

Weird

Explanation 0

N=3
n is odd and odd numbers are weird, so print Weird.

Sample Input 1

24

Sample Output 1

Not Weird

Explanation 1

N=24

n>20  and  is even, so it is not weird.

Code: 

import math

import os

import random

import re

import sys

if __name__ == '__main__':

    n = int(raw_input().strip())

    if n%2 != 0:

        print("Weird")

    else :

        if(n>=2 and n<=5):

            print("Not Weird")

        elif(n>=6 and n<=20):

            print("Weird")

        elif(n>20):

            print("Not Weird")

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